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Jul 15, 2013 Full Subtractor Design using Logical Gates (Verilog CODE) 08:23 Unknown 2 comments Email This BlogThis!
--D. Thiebaut 11:03, 24 April 2012 (EDT)
This lab should be done after the introduction lab on Verilog. It shows how to use two modules, one for the basic 3-bit full-adder (adding a to b with carry-in), and one that uses 4 of them to create a 4-bit adder with an output carry.
A full adder is a combinational logic that takes 3 bits, a, b, and carry-in, and outputs their sum, in the form of two bits, carry-out, and sum.
The figure below illustrates the circuit:
We now have several options to define this adder. One is functional, as illustrated in the next subsection. Next is a logical description, where we express the outputs in terms of their logical equation. The final is a gate level description. Pick the one that seem most interesting to you. They should all yield the same result in the next section, where we test them.
The timing diagram is fine, but a bit hard to read. A simpler test would be to have the simulation print out the value of the signals. This can be done by calling the predefined $monitor( ) function that will print to the console whenever there is a change in any of the signals.
Simply add the $monitor statement inside the always block:
Rerun the simulation and observe the output in the console of the ISim application:
We will now create a new Verilog module called MultiStages.v to create a full 4-bit adder.
The idea is simple. Best firewire audio interface. We want to add a 4-bit word to another 4-bit word and get a 4-bit sum, and a carry out.
All we need to do is write Verilog code that will replicate the full-adder encapsulated in SingleStage 4 times, and let the carry ripple from one stage to the next.
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You should be able to recognize the main features of the test module by now. The one that might be surprising is the for loop. The 16 * 16 terms simply means that we want to test all the combinations of a added to b. Since a and b are 4 bits, each can be one of 16 possible configurations, hence 16 * 16.
Jul 15, 2013 Full Subtractor Design using Logical Gates (Verilog CODE) 08:23 Unknown 2 comments Email This BlogThis!
--D. Thiebaut 11:03, 24 April 2012 (EDT)
This lab should be done after the introduction lab on Verilog. It shows how to use two modules, one for the basic 3-bit full-adder (adding a to b with carry-in), and one that uses 4 of them to create a 4-bit adder with an output carry.
A full adder is a combinational logic that takes 3 bits, a, b, and carry-in, and outputs their sum, in the form of two bits, carry-out, and sum.
The figure below illustrates the circuit:
We now have several options to define this adder. One is functional, as illustrated in the next subsection. Next is a logical description, where we express the outputs in terms of their logical equation. The final is a gate level description. Pick the one that seem most interesting to you. They should all yield the same result in the next section, where we test them.
The timing diagram is fine, but a bit hard to read. A simpler test would be to have the simulation print out the value of the signals. This can be done by calling the predefined $monitor( ) function that will print to the console whenever there is a change in any of the signals.
Simply add the $monitor statement inside the always block:
Rerun the simulation and observe the output in the console of the ISim application:
We will now create a new Verilog module called MultiStages.v to create a full 4-bit adder.
The idea is simple. Best firewire audio interface. We want to add a 4-bit word to another 4-bit word and get a 4-bit sum, and a carry out.
All we need to do is write Verilog code that will replicate the full-adder encapsulated in SingleStage 4 times, and let the carry ripple from one stage to the next.
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You should be able to recognize the main features of the test module by now. The one that might be surprising is the for loop. The 16 * 16 terms simply means that we want to test all the combinations of a added to b. Since a and b are 4 bits, each can be one of 16 possible configurations, hence 16 * 16.
Jul 15, 2013 Full Subtractor Design using Logical Gates (Verilog CODE) 08:23 Unknown 2 comments Email This BlogThis!
--D. Thiebaut 11:03, 24 April 2012 (EDT)
This lab should be done after the introduction lab on Verilog. It shows how to use two modules, one for the basic 3-bit full-adder (adding a to b with carry-in), and one that uses 4 of them to create a 4-bit adder with an output carry.
A full adder is a combinational logic that takes 3 bits, a, b, and carry-in, and outputs their sum, in the form of two bits, carry-out, and sum.
The figure below illustrates the circuit:
We now have several options to define this adder. One is functional, as illustrated in the next subsection. Next is a logical description, where we express the outputs in terms of their logical equation. The final is a gate level description. Pick the one that seem most interesting to you. They should all yield the same result in the next section, where we test them.
The timing diagram is fine, but a bit hard to read. A simpler test would be to have the simulation print out the value of the signals. This can be done by calling the predefined $monitor( ) function that will print to the console whenever there is a change in any of the signals.
Simply add the $monitor statement inside the always block:
Rerun the simulation and observe the output in the console of the ISim application:
We will now create a new Verilog module called MultiStages.v to create a full 4-bit adder.
The idea is simple. Best firewire audio interface. We want to add a 4-bit word to another 4-bit word and get a 4-bit sum, and a carry out.
All we need to do is write Verilog code that will replicate the full-adder encapsulated in SingleStage 4 times, and let the carry ripple from one stage to the next.
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You should be able to recognize the main features of the test module by now. The one that might be surprising is the for loop. The 16 * 16 terms simply means that we want to test all the combinations of a added to b. Since a and b are 4 bits, each can be one of 16 possible configurations, hence 16 * 16.